Explicit Specialization of Generic Class
This video tutorial explains the explicit specialization of generic class i.e overriding the generic class for a specific version of it in c++ programming.
You are gonna learn what happens when we do explicit specialization on a generic class, how to define a class for a datatype which will override the generic class for that datatype, what is the syntax to denote explicit specialization of a class in detail with example.
source code for this tutorial
#include <iostream> using namespace std; template <class Type> class MyClass{ Type p1; public: MyClass(Type p){ cout << "from the generic class conbstructor"<<endl; p1 = p; } void whatYouGot(){ cout << p1<<endl; } }; template <> class MyClass <int>{ int p1; public: MyClass(int p){ p1 = p; cout << "from the specific integer version class conbstructor"<<endl; } void whatYouGot(){ cout << p1<<endl; } }; int main() { MyClass <string> ob1("anil"); MyClass <int> ob2(22); ob1.whatYouGot(); ob2.whatYouGot(); return 0; }